
$\left(4+20\right)\div \left(1-\dfrac{1}{3}-40\%\right)$
$=24\div \left(1-\dfrac{1}{3}-\dfrac{2}{5}\right)$
$=24\div \left(1-\dfrac{5}{15}-\dfrac{6}{15}\right)$
$=24\div \dfrac{4}{15}$
$=24\times \dfrac{15}{4}$
$=90($盆)。
答:这批鲜花共需要购买$90$盆.

$\left(4+20\right)\div \left(1-\dfrac{1}{3}-40\%\right)$
$=24\div \left(1-\dfrac{1}{3}-\dfrac{2}{5}\right)$
$=24\div \left(1-\dfrac{5}{15}-\dfrac{6}{15}\right)$
$=24\div \dfrac{4}{15}$
$=24\times \dfrac{15}{4}$
$=90($盆)。
答:这批鲜花共需要购买$90$盆.